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Question
A gas expands from 1.5 to 6.5 L against a constant pressure of 0.5 atm and during this process the gas also absorbs 100 J of heat. The change in the internal energy of the gas is:
A gas expands from 1.5 to 6.5 L against a constant pressure of 0.5 atm and during this process the gas also absorbs 100 J of heat. The change in the internal energy of the gas is:
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Solution
The correct option is A −153.3 J
ΔU=q+w
q = heat absorbed = 100 J
w = work done = -PΔV
= - 0.5 x 5 atm L
= - 2.5 atm L
= - 253.3125 J
ΔU=−253.3125+100=−153.3 J
ΔU=q+w
q = heat absorbed = 100 J
w = work done = -PΔV
= - 0.5 x 5 atm L
= - 2.5 atm L
= - 253.3125 J
ΔU=−253.3125+100=−153.3 J
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