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Question
A gas expands from 6m3 to 8m3 in a container against a constant external pressure of 3 Pa. The work done by the gas is:
A gas expands from 6m3 to 8m3 in a container against a constant external pressure of 3 Pa. The work done by the gas is:
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Solution
The correct option is B - 6 J
For isothermal process under constant external pressure w=−Pext×dV=−Pext×(V2−V1)=−3(8−6)=−3(2)=−6J
This is the work done ON the gas. Question asks for work done BY the gas, which is =−w
For isothermal process under constant external pressure w=−Pext×dV=−Pext×(V2−V1)=−3(8−6)=−3(2)=−6J
This is the work done ON the gas. Question asks for work done BY the gas, which is =−w
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