A gas expands from a volume of $1 m^{3}$ to a volume of $2 m^{3}$ against an external pressure of $10^{5} N m^{- 2}$ . The work done by the gas will be:

10^{5} J

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10^{2} J

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10^{3} J

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None

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Solution

The correct option is A $10^{5} J$
Given,
$V_{1} = 1 m^{3}, V_{2} = 2 m^{3}, P = 10^{5} N m^{- 2}$

Since workdone (W) $= P Δ V$

$= P (V_{2} - V_{2})$

$= 10^{5} (2 - 1)$

$W = 10^{5} J$

or $W = 10^{2} K J$

Hence, the correct option is $A$

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A gas expands from a volume of 1 m3 to a volume of 2 m3 against an external pressure of 105 Nm−2. The work done by the gas will be:

The correct option is A 105 JGiven,V1=1m3,V2=2m3,P=105Nm−2Since workdone (W) =PΔV=P(V2−V2)=105(2−1)W=105Jor W=102KJHence, the correct option is A

A gas expands from a volume of $1 m^{3}$ to a volume of $2 m^{3}$ against an external pressure of $10^{5} N m^{- 2}$ . The work done by the gas will be:

The correct option is A $10^{5} J$
Given,
$V_{1} = 1 m^{3}, V_{2} = 2 m^{3}, P = 10^{5} N m^{- 2}$

Since workdone (W) $= P Δ V$

$= P (V_{2} - V_{2})$

$= 10^{5} (2 - 1)$

$W = 10^{5} J$

or $W = 10^{2} K J$

Hence, the correct option is $A$