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Ideal Gas Equation

A gas found t...

Question

A gas found to obey the law $p^{2} V$ constant. The initial temperature and volume are $T_{0} a n d V_{0}$ . If the gas expands to a volume $2 V_{0}$ , its final temperature becomes

$\sqrt{2} T_{0}$

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$2 T_{0}$

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$T_{0} / 2$

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$T_{0} / \sqrt{2}$

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Solution

The correct option is A
$\sqrt{2} T_{0}$

$p^{2} V = c o n s t a n t F o r a n i d e a l g a s : P V = n R T F r o m e q u a t i o n (1) a n d (2) (T^{2} / V) = c o n s t a n t T_{2} = \sqrt{\frac{V_{2}}{V_{1}}} T_{1} = \sqrt{2} T_{0}$

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A gas found to obey the law p2V constant. The initial temperature and volume are T0 and V0. If the gas expands to a volume 2V0, its final temperature becomes

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A gas found to obey the law $p^{2} V$ constant. The initial temperature and volume are $T_{0} a n d V_{0}$ . If the gas expands to a volume $2 V_{0}$ , its final temperature becomes

The correct option is A
$\sqrt{2} T_{0}$

$p^{2} V = c o n s t a n t F o r a n i d e a l g a s : P V = n R T F r o m e q u a t i o n (1) a n d (2) (T^{2} / V) = c o n s t a n t T_{2} = \sqrt{\frac{V_{2}}{V_{1}}} T_{1} = \sqrt{2} T_{0}$