A gas has a density of 3 g - L at S-T-P- What is its molar mass-A- 67-2 gB- 40 gC- 20-4 gD- 10 g

The correct option is A 67.2 gWe know, PM = ρ RT where, M = Molar mass ρ = Density of gas nbsp; At STP; T = 273 K, R = 0.0821 atm LK mol P = 1 atm ∴ M = ...

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Standard XII

Physics

Ideal Gas Equation from KTG

A gas has a d...

Question

A gas has a density of $3 g/L$ at S.T.P. What is its molar mass?

67.2 g

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40 g

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20.4 g

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10 g

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Solution

The correct option is A $67.2 g$
We know,
$P M = ρ R T$
where,
$M =$ Molar mass
$ρ =$ Density of gas
At STP;
$T = 273 K, R = 0.0821 \frac{atm-L}{K-mol}$
$P = 1 atm$
$∴ M = \frac{ρ R T}{P} = \frac{3 \times 0.0821 \times 273}{1}$
$\Rightarrow M = 67.2 g$

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Ideal Gas Equation from KTG

Standard XII Physics

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A gas has a density of 3 g/L at S.T.P. What is its molar mass?

The correct option is A 67.2 gWe know, PM=ρRT where, M= Molar mass ρ= Density of gas At STP; T=273 K,R=0.0821 atm-LK-mol P=1 atm ∴M=ρRTP=3×0.0821×2731 ⇒M=67.2 g

A gas has a density of $3 g/L$ at S.T.P. What is its molar mass?

The correct option is A $67.2 g$
We know,
$P M = ρ R T$
where,
$M =$ Molar mass
$ρ =$ Density of gas
At STP;
$T = 273 K, R = 0.0821 \frac{atm-L}{K-mol}$
$P = 1 atm$
$∴ M = \frac{ρ R T}{P} = \frac{3 \times 0.0821 \times 273}{1}$
$\Rightarrow M = 67.2 g$