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Question

A gas has a molecular diameter of 0.1 m. It also has a mean free path of 2.25 m. What is its density?

A
103
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B
102
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C
104
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D
105
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Solution

The correct option is A 103
Given :
Molecular diameter of a gas, d=0.1m.
Mean free path, l=2.25m.
The mean free path traversed by the molecules is given by
l=12πd2ρ
Therefor,
ρ=12πd2l
Using the given values we get,
ρ=12(3.14)(0.1)2(2.25)
ρ=10.0999
ρ=103

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