A gas has a pressure of 1.26 atm and occupies a volume of 7.40 L. If the gas is compressed to a volume of 2.93 L, what will its pressure?

2.58 atm

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3.18 atm

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3.99 atm

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4.24 atm

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Solution

The correct option is B
3.18 atm

According to Boyle's law: $P_{1} V_{1} = P_{2} V_{2}$

Here $P_{1} = 1.26 a t m : V_{2} = 2.93 L : V_{1} = 7.4 L$

$\Rightarrow P_{2} = \frac{1.26 \times 7.4}{2.93}$

$\Rightarrow P_{2} = 3.18 a t m$

Therefore, the pressure of gas = 3.18 atm

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A gas has a pressure of 1.26 atm and occupies a volume of 7.40 L. If the gas is compressed to a volume of 2.93 L, what will its pressure?

The correct option is B 3.18 atm According to Boyle's law: P1V1=P2V2 Here P1=1.26atm : V2=2.93L : V1=7.4L ⇒P2=1.26×7.42.93 ⇒P2=3.18 atm Therefore, the pressure of gas = 3.18 atm

The correct option is B
3.18 atm

According to Boyle's law: $P_{1} V_{1} = P_{2} V_{2}$

Here $P_{1} = 1.26 a t m : V_{2} = 2.93 L : V_{1} = 7.4 L$

$\Rightarrow P_{2} = \frac{1.26 \times 7.4}{2.93}$

$\Rightarrow P_{2} = 3.18 a t m$

Therefore, the pressure of gas = 3.18 atm