Question

A gas has a vapour density 11.2. The volume occupies by 1g of the gas at NTP is:

• A. 1 L
• B. 11.2 L
• C. 22.4 L
• D. 4 L

Answer 1

The correct option is A 1 L

Given vapour density = 11.26; mass = 1 g

Molecular mass = 2 $\times$ vapour density

$=2\times 11.2=22.4g$

Molecular mass = 22.4 L at S.T.P.

$\therefore$ 22.4 g = 22.4 L at S.T.P.

$\therefore 1g=\frac{22.4}{22.4}\times 1=1L.$

Hence, the correct option is $\text{A}$