A gas has a vapour density of 11.2. The volume occupied by 1 gram of the gas at STP will be

112 L

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224 L

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1 L

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10 L

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Solution

The correct option is C
1 L
Vapour density $= 11.2$
Molecular mass $= 11.2 \times 2 = 22.4$
$M a s s = 1 g A t S T P, P = 1 a t m T = 0 + 273 = 273 K Ideal Gas Equation P V = n R T = 1.00059 \approx 1 L$

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