Question

A gas has a vapour density of $11.2$. The volume occupied by $1\text{g}$ of the gas at STP is:

• A. $1\text{L}$
• B. $11.2\text{L}$
• C. $22.4\text{L}$
• D. $4\text{L}$

Answer 1

The correct option is A $1\text{L}$

We know that:
$\text{vapour density}=\frac{molarmass\left(numericalvalue\right)}{2}$
Molar mass of a gas $=2\times 11.2=22.4\text{g}$
we know that at STP one mole of gas occupies
22.4 L.
So 22.4 g of the given gas occuies 22.4 L .
Volume occupied by $1\text{g}$ compound at STP
$=\frac{22.4}{22.4}=1\text{L}$