A gas has a vapour density of 11.2. The volume occupied by 1g of the gas at STP is:
A
1L
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B
11.2L
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C
22.4L
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D
4L
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Solution
The correct option is A1L We know that: vapour density=molarmass(numericalvalue)2
Molar mass of a gas =2×11.2=22.4g
we know that at STP one mole of gas occupies
22.4 L.
So 22.4 g of the given gas occuies 22.4 L .
Volume occupied by 1g compound at STP =22.422.4=1L