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Question

A gas has a vapour density of 11.2. The volume occupied by 1 g of the gas at STP is:

A
1 L
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B
11.2 L
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C
22.4 L
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D
4 L
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Solution

The correct option is A 1 L
We know that:
vapour density=molar mass (numerical value)2
Molar mass of a gas =2×11.2=22.4 g
we know that at STP one mole of gas occupies
22.4 L.
So 22.4 g of the given gas occuies 22.4 L .
Volume occupied by 1 g compound at STP
=22.422.4=1 L

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