A gas has an average speed of $10 m / s$ and a collision frequency of $10$ $s^{- 1}$ . What is its mean free path?

1 m

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2 m

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3 m

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0.1 m

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Solution

The correct option is D $1 m$
Collision Frequency is the number of times a molecule of a gas collides with other molecules.
Reciprocal of that frequency is the time taken by the molecule to cover the free path.
We know that distance = $s p e e d \times t i m e$
Hence mean free path = $\frac{s p e e d}{f r e q u e n c y}$

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A gas has an average speed of 10m/s and a collision frequency of 10 s−1. What is its mean free path?

The correct option is D 1mCollision Frequency is the number of times a molecule of a gas collides with other molecules. Reciprocal of that frequency is the time taken by the molecule to cover the free path.We know that distance = speed×timeHence mean free path = speedfrequency

A gas has an average speed of $10 m / s$ and a collision frequency of $10$ $s^{- 1}$ . What is its mean free path?