A gas has an average speed of $10 m / s$ and an average time of $0.1 s$ between collisions. What is its mean free path?

1 m

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0.1 m

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2 m

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None of the above

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Solution

The correct option is A $1 m$
Mean free path of a body is defined as the distance covered by that body between two successive collisions.
Average speed of the girl $v_{a v g} = 10$ m/s
Time between two collisions $t = 0.1$ s
Mean free path $λ = v_{a v g} t = 10 \times 0.1 = 1$ m

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A gas has an average speed of 10m/s and an average time of 0.1s between collisions. What is its mean free path?

The correct option is A 1mMean free path of a body is defined as the distance covered by that body between two successive collisions. Average speed of the girl vavg=10 m/sTime between two collisions t=0.1 sMean free path λ=vavgt=10×0.1=1 m

A gas has an average speed of $10 m / s$ and an average time of $0.1 s$ between collisions. What is its mean free path?

The correct option is A $1 m$
Mean free path of a body is defined as the distance covered by that body between two successive collisions.
Average speed of the girl $v_{a v g} = 10$ m/s
Time between two collisions $t = 0.1$ s
Mean free path $λ = v_{a v g} t = 10 \times 0.1 = 1$ m