A gas in a 1 $m^{3}$ container has a molecular diameter of 0.1 m. There are 10 molecules. What is its mean free path?

2.25m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 2.25m
The mean free path of a molecule is given by the formula ( $λ$ ) $\frac{1}{\sqrt{2 π d^{2} n}}$
where d is the diameter of the molecules; n - number of molecules

$\frac{1}{\sqrt{2 π \times 0.1 \times 0.1 \times 10}} = 2.25 m$

Suggest Corrections

Similar questions

Q. A gas has a density of

10

particles

/ m^{3}

and a molecular diameter of

0.1

m. What is its mean free path?

Q. A gas has a molecular diameter of 0.1 m. It also has a mean free path of 2.25 m. What is its density?

Q. A gas has an average speed of

10 m / s

and an average time of

0.1 s

between collisions. What is its mean free path?

Q. A gas has an average speed of 10 m/s and a collision frequency of 10

s^{- 1}

. What is its mean free path?

In a cubical vessel $1 m \times 1 m \times 1 m$ the gas molecules of diameter $1.7 \times 10^{- 8} cm$ are at a temperature 300 K and a pressure of $10^{- 4} mm$ mercury. The mean free path of the gas molecule is

Join BYJU'S Learning Program

A gas in a 1 m3 container has a molecular diameter of 0.1 m. There are 10 molecules. What is its mean free path?

The correct option is B 2.25mThe mean free path of a molecule is given by the formula (λ) 1√2πd2n where d is the diameter of the molecules; n - number of molecules1√2π×0.1×0.1×10=2.25m

A gas in a 1 $m^{3}$ container has a molecular diameter of 0.1 m. There are 10 molecules. What is its mean free path?

The correct option is B 2.25m
The mean free path of a molecule is given by the formula ( $λ$ ) $\frac{1}{\sqrt{2 π d^{2} n}}$
where d is the diameter of the molecules; n - number of molecules

$\frac{1}{\sqrt{2 π \times 0.1 \times 0.1 \times 10}} = 2.25 m$