Question

A gas in an open container is heated from ${27}^{\circ }C$ to ${127}^{\circ }C$. The fraction of the original amount of the gas escaped in the container will be :

• A. 3/4
• B. 1/2
• C. 1/4
• D. 1/8

Answer 1

Answer: (C)

1/4

As of ideal gas equation, $P_1{V}_1=n_{1}R{T}_1$
$P_2{V}_2=n_{2}R{T}_2$
Since ${27}^{o}C=300K$ and ${127}^{o}C=400K$

$\frac{n_2}{n_1}=\frac{T_1}{T_2}=\frac{300}{400}=\frac{3}{4}$

$n_2=\frac{3}{4}{n}_1$

$Escaped=\frac{1}{4}$

Hence, the correct option is $C$