Question

A gas in an open container is heated from 27^{0C TO 1270C.} What will be the ratio of the gas left in the container to the original amount of gas?

• A. $\frac{3}{4}$
• B. $\frac{1}{4}$
• C. $\frac{1}{2}$
• D. $\frac{1}{8}$

Answer 1

The correct option is A

$\frac{3}{4}$

On heating a gas in a open container (P constt , V constt) , moles of gas go out.

Thus $n_1{T}_1$ = $n_2{T}_2$

Or $n_1$ $\times$ 300 = $n_2$ $\times$ 400

$\therefore$ $n_2$ = $\frac{3n_1}{4}$

$\therefore$ Fraction of moles of gas left

= $\frac{n_2}{n_1}$ = $\frac{3n_1}{4n_1}$ = $\frac{3}{4}$