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Question

A gas in an open container is treated from 27oC to 1270C. The fraction of original amount of gas remaining in the container will be:

A
34
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B
14
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C
12
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D
18
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Solution

The correct option is A 34
As we know that PV=nRT. Here pressure P and volume V are kept constant.

Here T1 = 300 K and T2 = 400 K

Let n1,n2 are the mole numbers at temp T1 and T2

So, n1T1=n2T2

n2n1=3/4.

So,n2=3n1/4.

So the correct option is A

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