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Question

A gas is allowed to expand in a well insulated container against a constant external pressure of 2.5 atm from an initial volume of 2.50 L to a final volume of 4.50 L. The change in internal energy ΔU of the gas in joules will be:

A
1136.25 J
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B
500 J
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C
505 J
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D
+505 J
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Solution

The correct option is C 505 J
ΔU=q+w
For adiabatic process, q = 0
ΔU=w
=P.ΔV
=2.5 atm ×(4.52.5)L
=2.5×2 Latm
=5×101.3J
=506.5 J
505 J

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