A gas is allowed to expand in a well insulated container against a constant external pressure of 2.5 atm from an initial volume of 2.50 L to a final volume of 4.50 L. The change in internal energy ΔU of the gas in joules will be:
A
1136.25J
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B
−500J
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C
−505J
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D
+505J
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Solution
The correct option is C−505J ΔU=q+w For adiabatic process, q = 0 ∴ΔU=w =−P.ΔV =−2.5atm×(4.5−2.5)L =−2.5×2Latm =−5×101.3J =−506.5J ≈−505J