A gas is at 1atm pressure with a volume 800cm3. When 100J of heat is supplied to the gas, it expands to 1L at constant pressure. The change in its internal energy is
A
80J
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B
−80J
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C
20J
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D
−20J
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Solution
The correct option is C80J The work done on the gas at constant pressure is, W=PΔV Thus, W = 1×(1−0.8) W=0.2atm−L=20J Now, heat supplied, Q=100J According to the first law of thermodynamics, Q = U + W Thus, U=100−20=80J