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Standard XII

Chemistry

Le Chatelier's Principle for Del N Equals to 0

A gas is cont...

Question

A gas is contained in a cylinder fitted with a frictionless piston. It expands against a constant pressure of 1 atm from a volume of 4L to 14L. In doing so, it absorbs 800J thermal energy from the surrounding. The $Δ E$ for the process is:

- 213.5J

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- 112J

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- 50J

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- 25J

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Solution

The correct option is A - 213.5J
$Δ E = q + w$ ; where,
$q =$ heat absorbed by system $= 800 J$
$w =$ work done on system $= - P Δ V$
$w = - 1 \times (14 - 4) = 10 a t m L = - 10 \times 101.325 J$
$Δ E = - 1013.25 + 800 J = - 213.25 J$
$Δ E ≃ - 213.5 J$

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A gas is contained in a cylinder fitted with a frictionless piston. It expands against a constant pressure of 1 atm from a volume of 4L to 14L. In doing so, it absorbs 800J thermal energy from the surrounding. The ΔE for the process is:

The correct option is A - 213.5JΔE=q+w; where, q= heat absorbed by system =800Jw= work done on system =−PΔVw=−1×(14−4)=10atmL=−10×101.325JΔE=−1013.25+800J=−213.25JΔE≃−213.5J

A gas is contained in a cylinder fitted with a frictionless piston. It expands against a constant pressure of 1 atm from a volume of 4L to 14L. In doing so, it absorbs 800J thermal energy from the surrounding. The $Δ E$ for the process is:

The correct option is A - 213.5J
$Δ E = q + w$ ; where,
$q =$ heat absorbed by system $= 800 J$
$w =$ work done on system $= - P Δ V$
$w = - 1 \times (14 - 4) = 10 a t m L = - 10 \times 101.325 J$
$Δ E = - 1013.25 + 800 J = - 213.25 J$
$Δ E ≃ - 213.5 J$