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Question
A gas is cooled and loses 50 J of heat. The gas contracts as it cools and work done on the system equal to 20 J is exchanged with the surroundings hence, ΔE is:
A gas is cooled and loses 50 J of heat. The gas contracts as it cools and work done on the system equal to 20 J is exchanged with the surroundings hence, ΔE is:
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Solution
The correct option is C −30 J
According to first law of thermodynamics △E=Q+W
Q=−50 J ( loses heat )
W=+20 J ( work is done on the gas )
Hence △E=−50+20
△E=−30J
Hence, option B is correct.
According to first law of thermodynamics △E=Q+W
Q=−50 J ( loses heat )
W=+20 J ( work is done on the gas )
Hence △E=−50+20
△E=−30J
Hence, option B is correct.
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