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Question

A gas is expanded from volume V0 to 2V0 under three different processes, as shown in the figure. Process 1 is isobaric process, process 2 is isothermal and process 3 is adiabatic. Let ΔU1,ΔU2 and ΔU3 be the change in the internal energy of the gas in these three processes, then:


A

ΔU1=ve;ΔU2=0;ΔU3=+ve

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B

ΔU1=+ve;ΔU2=0;ΔU3=+ve

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C

ΔU1=+ve;ΔU2=0;ΔU3=ve

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D

ΔU1=+ve;ΔU2=+ve;ΔU3=+ve

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Solution

The correct option is C

ΔU1=+ve;ΔU2=0;ΔU3=ve


ΔU1=+ve;ΔU2=0;ΔU3=ve


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