A gas is expanded from volume V 0 to 2 V 0 under three different processes- as shown in the figure- Process 1 is isobaric process- process 2 is isothermal and process 3 is adiabatic- Let - U 1- - U 2 and - U 3 be the change in the internal energy of the gas in these three processes- then-A- - U 1- ve - - U 2-0 - - U 3- veB- - U 1- ve - - U 2-0 - - U 3- veC- - U 1- ve- - U 2- ve - - U 3- veD- - U 1- ve - - U 2-0 - - U 3- ve

The correct option is B Δ U_1 = + ve ; Δ U_2 = 0; Δ U_3 = ve Δ U_1 = +ve ; Δ U_2 = 0; Δ U_3 = ve ...

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Internal Energy

A gas is expa...

Question

A gas is expanded from volume $V_{0} t o 2 V_{0}$ under three different processes, as shown in the figure. Process 1 is isobaric process, process 2 is isothermal and process 3 is adiabatic. Let $Δ U_{1}, Δ U_{2}$ and $Δ U_{3}$ be the change in the internal energy of the gas in these three processes, then:

$Δ U_{1} = - v e; Δ U_{2} = 0; Δ U_{3} = + v e$

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$Δ U_{1} = + v e; Δ U_{2} = 0; Δ U_{3} = + v e$

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$Δ U_{1} = + v e; Δ U_{2} = 0; Δ U_{3} = - v e$

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$Δ U_{1} = + v e; Δ U_{2} = + v e; Δ U_{3} = + v e$

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