Let the P , V and n be the pressure ,volume ,no of moles respectively initialy. T= 27c= 27 +273 K=300Kelvin therefore according to ideal gas equation we can write PV = n R T PV = n r 300 (T= 300) n =PV/300r Now since 1/3rd gas escaped remaining gas = 2n/3 now let T'' = new temperature PV = 2n/3 rT'' after putting value of n weget PV = 2 PV/900r r T'' Now eliminating PV from both sides and r r canceled we get T'' = 900/2 = 450 Kelvin = 450 -273=177 celcius So ans 450 kelvin or 177 celcius