A gas is in equilibrium at T kelvin. Mass of one molecule is m and, its component of velocity in x direction is vx. The mean of its v2x is represented by nkTm. Find n.
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Solution
v=vx^i+vy^j+vz^k v=√v2x+v2y+v2z for random motion vx=vy=vz v=√3vx v=√3kTm⇒√3vx=√3kTm v2x=kTm