A gas is initially at $1$ atm pressure. To compress it to $1 / 4$ th of its initial volume, pressure to be applied is:

1

atm

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2

atm

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4

atm

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1 / 4

atm

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Solution

The correct option is C $4$ atm
According to boyle's law,

$P_{1} V_{1} = P_{2} V_{2}$

$\Rightarrow 1. V = \frac{V}{4} . P_{2}$

$\Rightarrow P_{2} = 4 a t m$

Hence, the correct option is $C$

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A gas is initially at 1 atm pressure. To compress it to 1/4 th of its initial volume, pressure to be applied is:

The correct option is C 4 atmAccording to boyle's law,P1V1=P2V2⇒1.V=V4.P2⇒P2=4 atmHence, the correct option is C

A gas is initially at $1$ atm pressure. To compress it to $1 / 4$ th of its initial volume, pressure to be applied is:

The correct option is C $4$ atm
According to boyle's law,

$P_{1} V_{1} = P_{2} V_{2}$

$\Rightarrow 1. V = \frac{V}{4} . P_{2}$

$\Rightarrow P_{2} = 4 a t m$

Hence, the correct option is $C$