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Question

A gas is undergoing a cyclic process as shown in figure, where P0=2 bar and V0=7 m3. Find the workdone (W) by the gas and heat (Q) released by the gas in one cycle.


A
44×105 J, 44×105 J
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B
44×105 J, 44×105 J
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C
88×105 J, 44×105 J
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D
88×105 J, 88×105 J
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Solution

The correct option is B 44×105 J, 44×105 J
Given that,
P0=2 bar, V0=7 m3
As we know that,
Work done W= (Area enclosed by PV graph)
[-ve sign since cycle is anticlockwise]

W=πR1R2
=π(3P0P02)(3V0V02)
=πP0V0
=44×105 J
So, work done by the gas is 44×105 J

In a thermodynamic cyclic process,
ΣQ=ΣW
So, in this process,
Net heat transfer will be 44×105 J.
That means, value of heat released in this process is 44×105 J

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