A gas mixture consists of 2 moles of oxygen and 4 moles of argon at temperature $T$ . Neglecting all vibrational modes, the total internal energy of the system is

4 R T

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9 R T

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15 R T

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11 R T

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Solution

The correct option is D $11 R T$
The total internal energy of system is

$= U_{oxygen} + U_{argon} = n_{1} \frac{f_{1}}{2} R T + n_{2} \frac{f_{2}}{2} R T$

$= 2 \frac{5}{2} R T + 4 \frac{3}{2} R T = 5 R T + 6 R T = 11 R T$

(As $f_{1} = 5$ (for oxygen) and $f_{2} = 3$ (for argon))

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A gas mixture consists of 2 moles of oxygen and 4 moles of argon at temperature T. Neglecting all vibrational modes, the total internal energy of the system is

The correct option is D 11RTThe total internal energy of system is =Uoxygen+Uargon=n1f12RT+n2f22RT =252RT+432RT=5RT+6RT=11RT (As f1=5 (for oxygen) and f2=3 (for argon))

A gas mixture consists of 2 moles of oxygen and 4 moles of argon at temperature $T$ . Neglecting all vibrational modes, the total internal energy of the system is

The correct option is D $11 R T$
The total internal energy of system is

$= U_{oxygen} + U_{argon} = n_{1} \frac{f_{1}}{2} R T + n_{2} \frac{f_{2}}{2} R T$

$= 2 \frac{5}{2} R T + 4 \frac{3}{2} R T = 5 R T + 6 R T = 11 R T$

(As $f_{1} = 5$ (for oxygen) and $f_{2} = 3$ (for argon))