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Stoichiometric Calculations

A gas mixture...

Question

A gas mixture contains acetylene and carbondioxide. 20 litres of this mixture requires 20 litres of oxygen for complete combustion. If all gases are measured under similar conditions of temperature and pressure, the percentage of acetylene in the mixture is:

A

50%

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B

40%

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C

60%

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D

75%

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Solution

The correct option is B 40%
$C O_{2}$ won't get undergo combustion.

The reaction for the combustion of acetylene is $C_{2} H_{2} + 2.5 O_{2} \to 2 C O_{2} + H_{2} O$ .
The combustion of 1 mole (22.4 L) of acetylene will require 2.5 moles $(2.5 \times 22.4 = 56 L)$ of oxygen.
20L of oxygen will combine with $\frac{22.4}{56} \times 20 = 8$ L of acetylene.
Thus, the mixture contains 8L or $\frac{8}{20} \times 100 = 40$ % acetylene.

So, the correct option is $B$

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