Question

A gas mixture contains equal number of molecules of $N_2$ and $S{F}_6$, some of it is passed through a gaseous effusion apparatus. Calculate how many molecules of $N_2$ are present in the product gas for every 100 molecules of $S{F}_6$.( If answer is $X$, then give answer as $X/57$ is equal to)

Answer 1

Given that a gaseous mixture contains equal number of molecules of $N_2$ and $S{F}_6$.

Let $x$ be the number of molecules of $N_2$ present.

As we know,
$\frac{x}{100}=\sqrt{\frac{(32+6\times 19)}{28}}$
$\Rightarrow x=228$

Hence, $228$ molecules of $N_2$ are present.

$228/57=4$.