A gas mixture contains nitrogen and methane in a 7:4 ratio by weight. The ratio of their moles is:

7:4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4:7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1:1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1:2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 1:1
Number of moles = $\frac{M a s s}{M o l a r m a s s}$

$\frac{n_{1}}{n_{2}} = \frac{\frac{7 x}{28}}{\frac{4 x}{16}} = \frac{0.25 x}{0.25 x} = \frac{1}{1}$

Option C is correct.

Suggest Corrections

Similar questions

A vessel contains 0.16g of methane and 0.28g of nitrogen. The ratio of partial pressures of methane to nitrogen in the mixture is about:

1 : 4

1 : 4

1 : 4

Join BYJU'S Learning Program