A gas obeys the equation of state P(V-b) = RT (The parameter b is constant). The slope for an isochore will be:

Negative

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Zero

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R/(V-b)

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R/P

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Solution

The correct option is C
R/(V-b)

P(V-b) = RT

P = $\frac{R T}{V - b}$

P = $⟮ \frac{R}{V - b} ⟯ T + 0$

y = mx + c (y = P and x = T for isochore)

slope = $\frac{R}{V - b}$

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Similar questions

P (V - b) = R T

A gas obeys the equation of state P(V-b) = RT (The parameter b is constant). The slope for an isochore will be:

P (V_{m} - b) = R T

P (V - b) = R T

b

P (V - b) = R T

^{'} b^{'}

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