Question

A gas occupies 200 mL at a pressure of 0.820 bar at $20$. How much volume will it occupy when it is subjected to an external pressure of 1.025 bar at the same temperature?

(Write the value to the nearest integer)

Answer 1

$P_1=0.820bar$

$P_2=1.025bar$

$V_1=200ml$

$V_2=?$

Since temperature is constant therefore, by applying Boyle's law,

$P_1{V}_1=P_2{V}_2$ or $V_2=\frac{P_1{V}_1}{P_2}$

$V_2=\frac{\left(0.820bar\right)\times \left(200mL\right)}{1.025bar}=160ml$