Question

A gas occupies 400 cm³ at normal pressure. Find the volume occupied gas at a pressure of 60 cm of mercury, the temperature remaining constant.

Answer 1

Given: $$\begin{gathered} {\mathrm{V}}_1=400{\mathrm{cm}}^3{\mathrm{P}}_1=760 \\ {\mathrm{V}}_2=?{\mathrm{P}}_2=600 \end{gathered}$$

Formula: $\frac{{\mathrm{P}}_1{\mathrm{V}}_1}{{\mathrm{T}}_1}=\frac{{\mathrm{P}}_2{\mathrm{V}}_2}{{\mathrm{T}}_2}$

$$\begin{gathered} \frac{400\times 760}{\mathrm{T}}=\frac{{\mathrm{V}}_2\times 600}{T} \\ {\mathrm{V}}_2=\frac{400\times 760}{600} \\ {\mathrm{V}}_2=\frac{1520}{3} \\ {\mathrm{V}}_2=506.66\mathrm{cm}\mathrm{of}\mathrm{Hg} \end{gathered}$$

The volume occupied by the gas is 506.66 cm of Hg.