A gas occupies $600 m l$ at $27^{o} C$ and $730 m m$ pressure. What would be its volume at STP?

0.5244

lit.

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1.5244

lit.

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2.5244

lit

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3.5244

lit

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Solution

The correct option is A $0.5244$ lit.
$V_{1} = 600 m L T_{1} = 27 ° C = 273 + 27 = 300 K P_{1} = 730 m m \frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{273} \frac{730 \times 600}{300} = \frac{760 \times V_{2}}{273} V_{2} = 524.44 m L = 0.5244 L$ At STP, $T_{2} = 273 K P_{2} = 760 m m V_{2} = ?$

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