Question

A gas occupies 900.0 $mL$ at a temperature of 27${}^{0}C$. What is the volume at 132${}^{0}C$?

Answer 1

$V_1/T_1=V_2/T_2$

(900.0 $mL$) / (300.0 $K$) = ($x$) / (405.0 $K$); $x$ = 1215 $mL$