Question

# A gas occupies a volume of 2.5 L at 9×105Nm−2. Calculate the additional pressure required to decrease the volume of the gas to 1.51. Assume temperature is constant. 15*105 N m-2 9*105 N m-2 6*105 N m-2 24*105 N m-2

Solution

## The correct option is C 6*105 N m-2 Here, P1=9×105Nm−2,P2=? V1=2.5 L,V2=1.5 L From Boyle's law, P1V1=P2V2, we get P2=P1V1V2=9×105×2.51.5=15×105Nm−2 The additional pressure required is  ⟮15×105Nm−2⟯−⟮9×105Nm−2⟯=6×105Nm−2

Suggest corrections