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Question

A gas occupies a volume of 2.5 L at 9×105Nm2. Calculate the additional pressure required to decrease the volume of the gas to 1.51. Assume temperature is constant. 


  1. 15*105 N m-2

  2. 9*105 N m-2

  3. 6*105 N m-2

  4. 24*105 N m-2


Solution

The correct option is C

6*105 N m-2


Here, P1=9×105Nm2,P2=?

V1=2.5 L,V2=1.5 L

From Boyle's law, P1V1=P2V2, we get

P2=P1V1V2=9×105×2.51.5=15×105Nm2

The additional pressure required is  15×105Nm29×105Nm2=6×105Nm2

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