A gas occupies a volume of $300 c c$ at $27^{\circ}$ C and $620 m m$ pressure. Find the volume of the gas at $47^{\circ}$ C and $640 m m$ .

$260 c c$

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$310 c c$

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$390 c c$

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$450 c c$

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Solution

The correct option is B
$310 c c$

Given,
Intial temperature $T_{1}$ = $27^{\circ}$ C
Final temperature $T_{2}$ = $47^{\circ}$ C
Intial pressure $P_{1}$ = $620 m m$
Final pressure $P_{2}$ = $640 m m$
Intial volume $V_{1}$ = $300 c c$

Using Ideal gas equation,

$\frac{P_{1} V_{1}}{T_{1}}$ = $\frac{p_{2} V_{2}}{T_{2}}$

$\frac{620 \times 300}{300}$ = $\frac{640 \times V_{2}}{320}$

$V_{2}$ = $310 c c$

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A gas occupies a volume of 300 cc at 27∘C and 620 mm pressure. Find the volume of the gas at 47∘C and 640 mm.

The correct option is B 310 cc Given, Intial temperature T1 = 27∘C Final temperature T2 = 47∘C Intial pressure P1 = 620 mm Final pressure P2 = 640 mm Intial volume V1 = 300 cc Using Ideal gas equation, P1V1T1 = p2V2T2 620×300300 = 640×V2320 V2 = 310 cc

A gas occupies a volume of $300 c c$ at $27^{\circ}$ C and $620 m m$ pressure. Find the volume of the gas at $47^{\circ}$ C and $640 m m$ .