A gas occupies one litre under atomospheric pressure. What will be the volume of the same amount of gas under 750 mm of Hg the temperature ?

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Solution

Given

$V_{1} = 1$ litre
$P_{1} = 1$ atm
$V_{2} = ?$

$P_{2} = \frac{750}{760}$ atm (at same T)

$∵ (1 a t m = 760 m m)$

$P_{1} V_{1} = P_{2} V_{2}$

$1 \times 1 = \frac{750}{760} \times V_{2}$

$v_{2} = \frac{760}{750}$

$v_{2} = 1.0133 l i t r e$

$= 1013.3 m L$

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A gas occupies one litre under atomospheric pressure. What will be the volume of the same amount of gas under 750 mm of Hg the temperature ?

GivenV1=1 litreP1=1 atmV2=?P2=750760 atm (at same T) ∵(1 atm=760mm) P1V1=P2V21×1=750760×V2v2=760750v2=1.0133 litre=1013.3 mL

Given

$V_{1} = 1$ litre
$P_{1} = 1$ atm
$V_{2} = ?$

$P_{2} = \frac{750}{760}$ atm (at same T)

$∵ (1 a t m = 760 m m)$

$P_{1} V_{1} = P_{2} V_{2}$

$1 \times 1 = \frac{750}{760} \times V_{2}$

$v_{2} = \frac{760}{750}$

$v_{2} = 1.0133 l i t r e$

$= 1013.3 m L$