Question

A gas occupies $V$ litres at a certain temperature. Keeping its pressure constant, its volume can be reduced to half its initial volume at ${27}^{o}C$. The original temperature of the gas is:

• A. ${54}^{0}C$
• B. ${600}^{0}C$
• C. ${500}^{0}C$
• D. ${327}^{0}C$

Answer 1

The correct option is D ${327}^{0}C$

At a constant pressure, volume is proportional to the absolute temperature.

So, $\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Here, $V_1=2V$ (say)

$T_1=?$

$V_2=V$ (say)

$T_2=300$ $K$

Putting all the values, we get $T_1=600$ $K={327}^{\circ }C$

Hence, the correct answer is option $\text{D}$.