A gas of mass $32 g$ has a volume of 20 litres at S.T.P. Calculate the gram molecular weight of the gas.

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Solution

Step 1 Concept
The molecular weight (molar mass) is the mass of one particle of that gas multiplied by Avogadro's number $(6.02 x 10^{23}) .$
Step 2 Calculate the gram molecular weight of the gas
20 litres at S.T.P. weighs equal to $32 g$
1 litre at S.T.P. weighs equal to $\frac{32}{20} g$
$22.4$ litres at S.T.P. weighs equal to $\frac{32}{20} \times 22.4 = 35.84 g$

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A gas of mass 32g has a volume of 20 litres at S.T.P. Calculate the gram molecular weight of the gas.

A gas of mass $32 g$ has a volume of 20 litres at S.T.P. Calculate the gram molecular weight of the gas.