A gas of volume 2000ml is kept in a vessel at a pressure of 103 pascals at a temperature of 27∘ C. If the pressure is increased to 105 pascals at the same temperature, the volume of the gas becomes
20 ml
P1V1=P2V2
P1=103 pas, V1=2000ml
P2=105 pas, V2=?
2000×103=105×V2
V2=20ml