wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A gas park in two processes in which it is hcated from the same initial state 1 to the same final temperature. The processes are shown on the P - V diagram by the straight lines 1−3 and 1−2. 2 and 3 are the points on the same isothermal curve. Q1 and Q2 are the heat transfer along the two processes. Then
216711.png

A
Q1=Q2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Q1<Q2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Q1>Q2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Insufficient data
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Q1>Q2
here temperature will be same at point 2 and 3
now we see from the curve that heat will be transfer from point 1 to 2 and 3 respectively,
hence Q=CvdT, but it is not important that if temperature will increase "Q" will also increse
hence Q1>Q2 it transfer heat from point 1 to 2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon