A gas thermometer measures the temperature from the variation of pressure of a sample of gas. If the pressure measured at the melting point of lead is 2.20 times the pressure measured at the triple point of water, find the melting point of lead.

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Solution

Pressure measured at

$M_{p} = 2.2 \times$ Pressure at triple point

$T = \frac{P}{P_{t r}} \times 273.16$

$= \frac{2.2 \times P_{t r}}{P_{t r}} \times 273.16$

$= 2.2 \times 273.16 = 600.952 K$

= 601 K

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A gas thermometer measures the temperature from the variation of pressure of a sample of gas. If the pressure measured at the melting point of lead is 2.20 times the pressure measured at the triple point of water, find the melting point of lead.

Pressure measured at Mp=2.2× Pressure at triple point T=PPtr×273.16 =2.2×PtrPtr×273.16 =2.2×273.16=600.952K = 601 K

Pressure measured at

$M_{p} = 2.2 \times$ Pressure at triple point

$T = \frac{P}{P_{t r}} \times 273.16$

$= \frac{2.2 \times P_{t r}}{P_{t r}} \times 273.16$

$= 2.2 \times 273.16 = 600.952 K$

= 601 K