Question

A gas thermometer registers an absolute pressure corresponding to $325mm$ of mercury when in contact with water at the triple point . What pressure does it read when in contact with water at the normal boiling point ?

Answer 1

The ideal gas law, $PV=RT$

Volume remains constant,

$\frac{P_2}{P_1}=\frac{T_2}{T_1}$

Temperature of triple point = $T_1=273.16K$

Temperature of normal boiling point of water= $T_2=373.15K$

So, $P_2=325mm\times \frac{373.15}{273.16}$

$P_2=444mm$