A gas undergoes A to B through three different processes 1, 2 and 3 as shown in the figure. The heat supplied to the gas is Q1,Q2 and Q3 respectively, then
A
Q1=Q2=Q3
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B
Q1<Q2<Q3
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C
Q1>Q2>Q3
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D
Q1=Q3>Q2
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Solution
The correct option is CQ1>Q2>Q3
We know that in P-V graph, the work done for clockwise path is positive and negative for anticlockwise path. So, ΔW1=(+)ve,ΔW2=0,ΔW3=(−)ve
Internal energy depends on the initial and final points and is path independent. So, ΔU1=ΔU2=ΔU3
We know that, ΔQ=ΔU+ΔW and ΔU is same for all the three processes, So,Q1>Q2>Q3