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Question

# A gas undergoes change from state A to state B. In this process, the heat absorbed and work done by the gas is 5J and 8J, respectively. Now gas is brought back at A by another process during which 3J of heat is evolved. In this reverse process of B to A:

A
10 J of the work will be done by the gas.
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B
6 J of the work will be done by the gas.
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C
10 J of the work will be done by the surrounding on gas.
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D
6 J of the work will be done by the surrounding on gas
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Solution

## The correct option is D 6 J of the work will be done by the surrounding on gas ΔUAB=q+w=+5+(−8)=−3 q=−3,ΔUBA=+3 ΔUBA=q+w ⇒3=−3+w⇒w=+6 ΔUBC=−5kJmol−1,qAB=2kJmol−1 WAB=−5kJmol−1,WCA=3kJmol−1 (work done on the system).

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