A gas which diffuses 4 time slowly that $H_{2}$ gas is :

H_{2} S

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O_{2}

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C H_{4}

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S O_{2}

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Solution

The correct option is C $O_{2}$
Let the molecular weight of gas be $M_{X} .$
$∴ \frac{r_{H_{2}}}{r_{X}} = \sqrt{\frac{M_{X}}{M_{H_{2}}}}$
The rate should be times the rate of diffusion of Hydrogen
Given $r_{H_{2}} = 4 r_{2}$ and $M_{H_{2}} = 2$
$4 = \sqrt{\frac{M_{X}}{2}}$
Squaring on both sides.
$16 = \frac{M_{X}}{2}$
$M_{X} = 32$
In the given options gas $O_{2}$ has molecular weight .
Hence $O_{2}$ diffuses 4 times slowly than $H_{2}$ gas.

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A gas which diffuses 4 time slowly that H2 gas is :

A gas which diffuses 4 time slowly that $H_{2}$ gas is :