A gas $X$ bleaches the colour of flowers by reduction while the other gas $Y$ bleaches by oxidation. These two gases $X$ and $Y$ are respectively :

C O

and

C O_{2}

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N H_{3}

and

S O_{3}

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C O_{2}

and

B r_{2}

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S O_{2}

and

C l_{2}

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Solution

The correct option is B $S O_{2}$ and $C l_{2}$
The bleaching action by chlorine is based on oxidation, which means it requires nascent oxygen for bleaching action while bleaching by sulphur dioxide is based on reduction which means it uses nascent hydrogen.
The reactions are given below:
$S O_{2} + 2 H_{2} O \to H_{2} S O_{4} + 2 [H]$
$C l_{2} + H_{2} O \to H C l + H O C l$
$H O C l \to H C l + [O]$

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