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Question

A gas ′X′ is dissolved in water at ′2′ bar pressure. Its mole fraction is 0.02 in solution. The mole fraction of water when the pressure of gas is doubled at the same temperature is:

A
0.04
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B
0.98
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C
0.96
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D
0.02
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Solution

The correct option is B 0.96
P1=PoX1
2=0.02Po
Let the pressure be doubled , P2
then, 4=PoX2
so we can write that :
P1P2=X1X2
24=0.02X2
X2=0.02×42=0.04
now,
Xwater=1Xsolute
Xwater=1Xsolute=0.04=0.96

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