A gas 'X', when dissolved in water heat, is evolved. Then solubility of 'X' will increase at:

low pressure, high temperature

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low pressure, low temperature

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high pressure, high temperature

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high pressure, low temperature

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Solution

The correct option is C high pressure, low temperature
$X (g) + H_{2} O (l) ⇌ s o l u t i o n; △ H < 0$

Since, $△ H < 0$ , the reaction is exothermic. So by applying Le Chatelier's principle, we can see that on increasing the temperature, the reaction shift towards the reactant side.

So, the favourable condition for temperature is low temperature.

Now, when gas is dissolved in water, its volume decreases. So, an increase of pressure will favour dissolution of gas in a liquid.

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